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Algorithm for Half Loss and Half Win in Betting

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Post time 10-2-2024 06:36:16 | Show all posts |Read mode


Recently, there have been discussions about the concepts of "half win" and "half loss." Let me explain this to those who are new to accumulator bets, while experienced punters can skip this.

Calculating a single game's "half win" or "half loss" is straightforward. In the case of a "half loss," you lose half of your stake. For instance, if you wagered $100 on a selection with odds higher than 2.25 (equivalent to over 2 goals/2.5 goals), and only 2 goals are scored, you lose half of your stake, and the remaining $50 is returned. Conversely, if you bet on under 2.25 goals and there are 2 goals scored, you win half. Your stake remains the same, but the odds are halved. For instance, if the odds were 0.9, they would become 0.45.

Now, let's discuss accumulator bets. Although it may seem a bit more complex, with the right approach, it's easy to calculate. If you can't identify errors in the settlement, that would be unfortunate.

Firstly, for "half win" calculations, since accumulators use only decimal odds (including the odds of the selection itself), and they are always greater than 1 point something. If you use the Hong Kong odds (represented as 0 points something), it would result in decreasing values when multiplied. Therefore, we only consider decimal odds in accumulators. For a 4-fold accumulator with one selection being a "half win," the odds for that selection are halved. For example, if the original odds were 1.8, they would become (1.8 + 1) / 2 = 1.4. It's evident that a "half win" doesn't mean you win only half; it's actually more than that.

Now, for the troublesome "half loss." Firstly, understand that "half loss" refers to losing half of the stake. For a 4-fold accumulator with one selection being a "half loss," you first halve the stake (e.g., $100 becomes $50), and then multiply it by the other three selections' odds. The "half loss" selection's odds are not considered, as you've already lost half of your stake because of it. To illustrate, if two selections in a $100 4-fold accumulator are "half losses," the calculation would be $100 / 2 = $50, then $50 / 2 = $25, and you use $25 to multiply the other two selections' odds.

In summary, "half loss" in smaller accumulators is considered a good outcome, as it often leads to breaking even. I hope this simplified explanation helps newcomers understand the concepts. The main goal is to be able to identify errors in bookmakers' settlements easily and avoid any losses.
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Post time 10-2-2024 07:06:34 | Show all posts
This algorithm is quite good.
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