Calculating the Return Rate of Betting on Single Dice in Sic Bo

Kabir903

Here is the translation of your text:

"I'm not satisfied with losing to that damn game, so I started thinking irrationally. Please correct me if I'm wrong or just ignore it.

First is the triplet problem:
Because I'm so frustrated, let's start with permutations and combinations.

Assume there are N points on line A, and the probability of randomly selecting any point is the same. Then, if two point selectors simultaneously randomly select point E, the probability of both of them selecting point E is E/N * E/N.

So, the probability of a triplet appearing is 2/216 = 0.00926 = 0.926%.

With a payout rate of 30 for a triplet, the expected return is 0.2778, with a risk of 99.074%.

The probability of appearing twice in a row is 42.67% to the power of -4 (approximately the probability of winning the grand prize in a large supermarket lottery... those who are confident can try it).

Next is the big/small problem.
Based on the above, the probability of each big/small group is 49%.

Therefore, it can be seen that, overall, betting on big/small is a guaranteed loss.

There is a psychological phenomenon called the gambler's fallacy, which states that the probability of an event in a random sequence is independent of previous events. In other words, the probability of an event occurring is not increased by previous events.

This means that betting on big/small is always a 49% probability.

If you bet wrong this time, it will still be a 50% probability next time.

Therefore, it can be seen that, overall, betting on big/small is a guaranteed loss. Betting on a triplet has an incomparable risk-reward ratio."

Please note that some parts may need further clarification or correction based on the context.

Indra55

No one likes to lose, and I'm no exception.